7(y-3)=4(2y+1)-21

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Solution for 7(y-3)=4(2y+1)-21 equation: 



7(y-3)=4(2y+1)-21

We move all terms to the left:

7(y-3)-(4(2y+1)-21)=0

We multiply parentheses

7y-(4(2y+1)-21)-21=0



We calculate terms in parentheses: -(4(2y+1)-21), so:

4(2y+1)-21

We multiply parentheses

8y+4-21

We add all the numbers together, and all the variables

8y-17

Back to the equation:

-(8y-17)



We get rid of parentheses

7y-8y+17-21=0

We add all the numbers together, and all the variables

-1y-4=0

We move all terms containing y to the left, all other terms to the right

-y=4

y=4/-1

y=-4

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