(2r+3)=(3r+5)

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Solution for (2r+3)=(3r+5) equation: 



(2r+3)=(3r+5)

We move all terms to the left:

(2r+3)-((3r+5))=0

We get rid of parentheses

2r-((3r+5))+3=0



We calculate terms in parentheses: -((3r+5)), so:

(3r+5)

We get rid of parentheses

3r+5

Back to the equation:

-(3r+5)



We get rid of parentheses

2r-3r-5+3=0

We add all the numbers together, and all the variables

-1r-2=0

We move all terms containing r to the left, all other terms to the right

-r=2

r=2/-1

r=-2

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