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5/2x=49-x
We move all terms to the left:
5/2x-(49-x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
5/2x-(-1x+49)=0
We get rid of parentheses
5/2x+1x-49=0
We multiply all the terms by the denominator
1x*2x-49*2x+5=0
Wy multiply elements
2x^2-98x+5=0
a = 2; b = -98; c = +5;
Δ = b2-4ac
Δ = -982-4·2·5
Δ = 9564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9564}=\sqrt{4*2391}=\sqrt{4}*\sqrt{2391}=2\sqrt{2391}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-2\sqrt{2391}}{2*2}=\frac{98-2\sqrt{2391}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+2\sqrt{2391}}{2*2}=\frac{98+2\sqrt{2391}}{4} $
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