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4x+2(x-5)=3(2x-12)
We move all terms to the left:
4x+2(x-5)-(3(2x-12))=0
We multiply parentheses
4x+2x-(3(2x-12))-10=0
We calculate terms in parentheses: -(3(2x-12)), so:We add all the numbers together, and all the variables
3(2x-12)
We multiply parentheses
6x-36
Back to the equation:
-(6x-36)
6x-(6x-36)-10=0
We get rid of parentheses
6x-6x+36-10=0
We add all the numbers together, and all the variables
26!=0
There is no solution for this equation
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