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660+3/2x=2x
We move all terms to the left:
660+3/2x-(2x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-2x+3/2x+660=0
We multiply all the terms by the denominator
-2x*2x+660*2x+3=0
Wy multiply elements
-4x^2+1320x+3=0
a = -4; b = 1320; c = +3;
Δ = b2-4ac
Δ = 13202-4·(-4)·3
Δ = 1742448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1742448}=\sqrt{16*108903}=\sqrt{16}*\sqrt{108903}=4\sqrt{108903}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1320)-4\sqrt{108903}}{2*-4}=\frac{-1320-4\sqrt{108903}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1320)+4\sqrt{108903}}{2*-4}=\frac{-1320+4\sqrt{108903}}{-8} $
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