4(3x-2)+2x=6x-12-5x

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Solution for 4(3x-2)+2x=6x-12-5x equation: 



4(3x-2)+2x=6x-12-5x

We move all terms to the left:

4(3x-2)+2x-(6x-12-5x)=0

We add all the numbers together, and all the variables

4(3x-2)+2x-(x-12)=0

We add all the numbers together, and all the variables

2x+4(3x-2)-(x-12)=0

We multiply parentheses

2x+12x-(x-12)-8=0

We get rid of parentheses

2x+12x-x+12-8=0

We add all the numbers together, and all the variables

13x+4=0

We move all terms containing x to the left, all other terms to the right

13x=-4

x=-4/13

x=-4/13

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