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(4x+9)(3x-15)=0
We multiply parentheses ..
(+12x^2-60x+27x-135)=0
We get rid of parentheses
12x^2-60x+27x-135=0
We add all the numbers together, and all the variables
12x^2-33x-135=0
a = 12; b = -33; c = -135;
Δ = b2-4ac
Δ = -332-4·12·(-135)
Δ = 7569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7569}=87$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-87}{2*12}=\frac{-54}{24} =-2+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+87}{2*12}=\frac{120}{24} =5 $
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