4m=3(m+2)+m-6

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Solution for 4m=3(m+2)+m-6 equation: 



4m=3(m+2)+m-6

We move all terms to the left:

4m-(3(m+2)+m-6)=0



We calculate terms in parentheses: -(3(m+2)+m-6), so:

3(m+2)+m-6

We add all the numbers together, and all the variables

m+3(m+2)-6

We multiply parentheses

m+3m+6-6

We add all the numbers together, and all the variables

4m

Back to the equation:

-(4m)



We add all the numbers together, and all the variables

=0

m=0/1

m=0

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