3(y+1)=2(4-y)

Solution for 3(y+1)=2(4-y) equation:

3(y+1)=2(4-y)

We move all terms to the left:

3(y+1)-(2(4-y))=0

We add all the numbers together, and all the variables

3(y+1)-(2(-1y+4))=0

We multiply parentheses

3y-(2(-1y+4))+3=0


We calculate terms in parentheses: -(2(-1y+4)), so:

2(-1y+4)

We multiply parentheses

-2y+8

Back to the equation:

-(-2y+8)


We get rid of parentheses

3y+2y-8+3=0

We add all the numbers together, and all the variables

5y-5=0

We move all terms containing y to the left, all other terms to the right

5y=5

y=5/5

y=1