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5x-3x(x-4)+2(x-5)=30
We move all terms to the left:
5x-3x(x-4)+2(x-5)-(30)=0
We multiply parentheses
-3x^2+5x+12x+2x-10-30=0
We add all the numbers together, and all the variables
-3x^2+19x-40=0
a = -3; b = 19; c = -40;
Δ = b2-4ac
Δ = 192-4·(-3)·(-40)
Δ = -119
Delta is less than zero, so there is no solution for the equation
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