1-3(6x-15)=1/2(10x-4)

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Solution for 1-3(6x-15)=1/2(10x-4) equation: 



1-3(6x-15)=1/2(10x-4)

We move all terms to the left:

1-3(6x-15)-(1/2(10x-4))=0



Domain of the equation: 2(10x-4))!=0

x∈R



We multiply parentheses

-18x-(1/2(10x-4))+45+1=0

We multiply all the terms by the denominator


-18x*2(10x-4))-(1+45*2(10x-4))+1*2(10x-4))=0

We add all the numbers together, and all the variables

-18x*2(10x-4))-(1+45*2(10x-4))+1*2(10x=0

Wy multiply elements

-36x^2(1+180x^2(1=0

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