4d-5d(d-1)=3-d+2

Solution for 4d-5d(d-1)=3-d+2 equation:

4d-5d(d-1)=3-d+2

We move all terms to the left:

4d-5d(d-1)-(3-d+2)=0

We add all the numbers together, and all the variables

4d-5d(d-1)-(-1d+5)=0

We multiply parentheses

-5d^2+4d+5d-(-1d+5)=0

We get rid of parentheses

-5d^2+4d+5d+1d-5=0

We add all the numbers together, and all the variables

-5d^2+10d-5=0

a = -5; b = 10; c = -5;
Δ = b2-4ac
Δ = 102-4·(-5)·(-5)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$d=\frac{-b}{2a}=\frac{-10}{-10}=1$