-5(x+3)(2x-1)=(2x+3)(4-5x)

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Solution for -5(x+3)(2x-1)=(2x+3)(4-5x) equation:



-5(x+3)(2x-1)=(2x+3)(4-5x)
We move all terms to the left:
-5(x+3)(2x-1)-((2x+3)(4-5x))=0
We add all the numbers together, and all the variables
-5(x+3)(2x-1)-((2x+3)(-5x+4))=0
We multiply parentheses ..
-5(+2x^2-1x+6x-3)-((2x+3)(-5x+4))=0
We calculate terms in parentheses: -((2x+3)(-5x+4)), so:
(2x+3)(-5x+4)
We multiply parentheses ..
(-10x^2+8x-15x+12)
We get rid of parentheses
-10x^2+8x-15x+12
We add all the numbers together, and all the variables
-10x^2-7x+12
Back to the equation:
-(-10x^2-7x+12)
We multiply parentheses
-10x^2-(-10x^2-7x+12)+5x-30x+15=0
We get rid of parentheses
-10x^2+10x^2+7x+5x-30x-12+15=0
We add all the numbers together, and all the variables
-18x+3=0
We move all terms containing x to the left, all other terms to the right
-18x=-3
x=-3/-18
x=1/6

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