120x2-98x-120=0

Solution for 120x2-98x-120=0 equation:

120x^2-98x-120=0

a = 120; b = -98; c = -120;
Δ = b2-4ac
Δ = -982-4·120·(-120)
Δ = 67204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{67204}=\sqrt{4*16801}=\sqrt{4}*\sqrt{16801}=2\sqrt{16801}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-2\sqrt{16801}}{2*120}=\frac{98-2\sqrt{16801}}{240}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+2\sqrt{16801}}{2*120}=\frac{98+2\sqrt{16801}}{240}
$