2(2x+2)-3(3x-4)=40

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Solution for 2(2x+2)-3(3x-4)=40 equation: 



2(2x+2)-3(3x-4)=40

We move all terms to the left:

2(2x+2)-3(3x-4)-(40)=0

We multiply parentheses

4x-9x+4+12-40=0

We add all the numbers together, and all the variables

-5x-24=0

We move all terms containing x to the left, all other terms to the right

-5x=24

x=24/-5

x=-4+4/5

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