3(x-7)+7x=41

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Solution for 3(x-7)+7x=41 equation:



3(x-7)+7x=41
We move all terms to the left:
3(x-7)+7x-(41)=0
We add all the numbers together, and all the variables
7x+3(x-7)-41=0
We multiply parentheses
7x+3x-21-41=0
We add all the numbers together, and all the variables
10x-62=0
We move all terms containing x to the left, all other terms to the right
10x=62
x=62/10
x=6+1/5

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