4=6x(18x+1)

Solution for 4=6x(18x+1) equation:

4=6x(18x+1)

We move all terms to the left:

4-(6x(18x+1))=0


We calculate terms in parentheses: -(6x(18x+1)), so:

6x(18x+1)

We multiply parentheses

108x^2+6x

Back to the equation:

-(108x^2+6x)


We get rid of parentheses

-108x^2-6x+4=0

a = -108; b = -6; c = +4;
Δ = b2-4ac
Δ = -62-4·(-108)·4
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-42}{2*-108}=\frac{-36}{-216}
=1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+42}{2*-108}=\frac{48}{-216}
=-2/9
$