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-3m^2+6m+24=0
a = -3; b = 6; c = +24;
Δ = b2-4ac
Δ = 62-4·(-3)·24
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-18}{2*-3}=\frac{-24}{-6} =+4 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+18}{2*-3}=\frac{12}{-6} =-2 $
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