3z2-12z+12=0

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Solution for 3z2-12z+12=0 equation: 



3z^2-12z+12=0

a = 3; b = -12; c = +12;
Δ = b2-4ac
Δ = -122-4·3·12
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{12}{6}=2$

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