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-6m^2+3m+4=0
a = -6; b = 3; c = +4;
Δ = b2-4ac
Δ = 32-4·(-6)·4
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{105}}{2*-6}=\frac{-3-\sqrt{105}}{-12} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{105}}{2*-6}=\frac{-3+\sqrt{105}}{-12} $
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