4/5y+y=72

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Solution for 4/5y+y=72 equation:



4/5y+y=72
We move all terms to the left:
4/5y+y-(72)=0
Domain of the equation: 5y!=0
y!=0/5
y!=0
y∈R
We add all the numbers together, and all the variables
y+4/5y-72=0
We multiply all the terms by the denominator
y*5y-72*5y+4=0
Wy multiply elements
5y^2-360y+4=0
a = 5; b = -360; c = +4;
Δ = b2-4ac
Δ = -3602-4·5·4
Δ = 129520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{129520}=\sqrt{16*8095}=\sqrt{16}*\sqrt{8095}=4\sqrt{8095}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-360)-4\sqrt{8095}}{2*5}=\frac{360-4\sqrt{8095}}{10} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-360)+4\sqrt{8095}}{2*5}=\frac{360+4\sqrt{8095}}{10} $

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