5y2=22y+15

Solution for 5y2=22y+15 equation:

5y^2=22y+15

We move all terms to the left:

5y^2-(22y+15)=0

We get rid of parentheses

5y^2-22y-15=0

a = 5; b = -22; c = -15;
Δ = b2-4ac
Δ = -222-4·5·(-15)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-28}{2*5}=\frac{-6}{10}
=-3/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+28}{2*5}=\frac{50}{10}
=5
$