4/3x+1=1/x

Solution for 4/3x+1=1/x equation:

4/3x+1=1/x

We move all terms to the left:

4/3x+1-(1/x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

4/3x-(+1/x)+1=0

We get rid of parentheses

4/3x-1/x+1=0

We calculate fractions


4x/3x^2+(-3x)/3x^2+1=0

We multiply all the terms by the denominator


4x+(-3x)+1*3x^2=0

Wy multiply elements

3x^2+4x+(-3x)=0

We get rid of parentheses

3x^2+4x-3x=0

We add all the numbers together, and all the variables

3x^2+x=0

a = 3; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·3·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*3}=\frac{-2}{6}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*3}=\frac{0}{6}
=0
$