4(7r-3)=128

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Solution for 4(7r-3)=128 equation: 



4(7r-3)=128

We move all terms to the left:

4(7r-3)-(128)=0

We multiply parentheses

28r-12-128=0

We add all the numbers together, and all the variables

28r-140=0

We move all terms containing r to the left, all other terms to the right

28r=140

r=140/28

r=5

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