4+2(x-5)=x+41

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Solution for 4+2(x-5)=x+41 equation: 



4+2(x-5)=x+41

We move all terms to the left:

4+2(x-5)-(x+41)=0

We multiply parentheses

2x-(x+41)-10+4=0

We get rid of parentheses

2x-x-41-10+4=0

We add all the numbers together, and all the variables

x-47=0

We move all terms containing x to the left, all other terms to the right

x=47

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