25=1/3(3k-12

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Solution for 25=1/3(3k-12 equation: 



25=1/3(3k-12

We move all terms to the left:

25-(1/3(3k-12)=0



Domain of the equation: 3(3k-12)+25!=0

We move all terms containing k to the left, all other terms to the right

3(3k-12)!=-25

k∈R



We multiply all the terms by the denominator


-(1=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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