4(m-3)+7m=27

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Solution for 4(m-3)+7m=27 equation: 



4(m-3)+7m=27

We move all terms to the left:

4(m-3)+7m-(27)=0

We add all the numbers together, and all the variables

7m+4(m-3)-27=0

We multiply parentheses

7m+4m-12-27=0

We add all the numbers together, and all the variables

11m-39=0

We move all terms containing m to the left, all other terms to the right

11m=39

m=39/11

m=3+6/11

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