24/b=8b=9

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Solution for 24/b=8b=9 equation:



24/b=8b=9
We move all terms to the left:
24/b-(8b)=0
Domain of the equation: b!=0
b∈R
We add all the numbers together, and all the variables
-8b+24/b=0
We multiply all the terms by the denominator
-8b*b+24=0
Wy multiply elements
-8b^2+24=0
a = -8; b = 0; c = +24;
Δ = b2-4ac
Δ = 02-4·(-8)·24
Δ = 768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{768}=\sqrt{256*3}=\sqrt{256}*\sqrt{3}=16\sqrt{3}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{3}}{2*-8}=\frac{0-16\sqrt{3}}{-16} =-\frac{16\sqrt{3}}{-16} =-\frac{\sqrt{3}}{-1} $
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{3}}{2*-8}=\frac{0+16\sqrt{3}}{-16} =\frac{16\sqrt{3}}{-16} =\frac{\sqrt{3}}{-1} $

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