4+(6+x)=(12+x)-20

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Solution for 4+(6+x)=(12+x)-20 equation: 



4+(6+x)=(12+x)-20

We move all terms to the left:

4+(6+x)-((12+x)-20)=0

We add all the numbers together, and all the variables

(x+6)-((x+12)-20)+4=0

We get rid of parentheses

x-((x+12)-20)+6+4=0



We calculate terms in parentheses: -((x+12)-20), so:

(x+12)-20

We get rid of parentheses

x+12-20

We add all the numbers together, and all the variables

x-8

Back to the equation:

-(x-8)



We add all the numbers together, and all the variables

x-(x-8)+10=0

We get rid of parentheses

x-x+8+10=0

We add all the numbers together, and all the variables

18!=0

There is no solution for this equation

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