8(x-4)-5(2x-8)=40

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Solution for 8(x-4)-5(2x-8)=40 equation: 



8(x-4)-5(2x-8)=40

We move all terms to the left:

8(x-4)-5(2x-8)-(40)=0

We multiply parentheses

8x-10x-32+40-40=0

We add all the numbers together, and all the variables

-2x-32=0

We move all terms containing x to the left, all other terms to the right

-2x=32

x=32/-2

x=-16

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