4(y-2)=3(2y+12)

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Solution for 4(y-2)=3(2y+12) equation: 



4(y-2)=3(2y+12)

We move all terms to the left:

4(y-2)-(3(2y+12))=0

We multiply parentheses

4y-(3(2y+12))-8=0



We calculate terms in parentheses: -(3(2y+12)), so:

3(2y+12)

We multiply parentheses

6y+36

Back to the equation:

-(6y+36)



We get rid of parentheses

4y-6y-36-8=0

We add all the numbers together, and all the variables

-2y-44=0

We move all terms containing y to the left, all other terms to the right

-2y=44

y=44/-2

y=-22

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