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3w(5w-1)=-10w+2
We move all terms to the left:
3w(5w-1)-(-10w+2)=0
We multiply parentheses
15w^2-3w-(-10w+2)=0
We get rid of parentheses
15w^2-3w+10w-2=0
We add all the numbers together, and all the variables
15w^2+7w-2=0
a = 15; b = 7; c = -2;
Δ = b2-4ac
Δ = 72-4·15·(-2)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-13}{2*15}=\frac{-20}{30} =-2/3 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+13}{2*15}=\frac{6}{30} =1/5 $
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