(3a+3)(a+2)=5

Solution for (3a+3)(a+2)=5 equation:

(3a+3)(a+2)=5

We move all terms to the left:

(3a+3)(a+2)-(5)=0

We multiply parentheses ..

(+3a^2+6a+3a+6)-5=0

We get rid of parentheses

3a^2+6a+3a+6-5=0

We add all the numbers together, and all the variables

3a^2+9a+1=0

a = 3; b = 9; c = +1;
Δ = b2-4ac
Δ = 92-4·3·1
Δ = 69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{69}}{2*3}=\frac{-9-\sqrt{69}}{6}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{69}}{2*3}=\frac{-9+\sqrt{69}}{6}
$