(100+5x)*(100-4x)=0

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Solution for (100+5x)*(100-4x)=0 equation:



(100+5x)(100-4x)=0
We add all the numbers together, and all the variables
(5x+100)(-4x+100)=0
We multiply parentheses ..
(-20x^2+500x-400x+10000)=0
We get rid of parentheses
-20x^2+500x-400x+10000=0
We add all the numbers together, and all the variables
-20x^2+100x+10000=0
a = -20; b = 100; c = +10000;
Δ = b2-4ac
Δ = 1002-4·(-20)·10000
Δ = 810000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{810000}=900$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-900}{2*-20}=\frac{-1000}{-40} =+25 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+900}{2*-20}=\frac{800}{-40} =-20 $

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