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4(x-3)=2(x+11)
We move all terms to the left:
4(x-3)-(2(x+11))=0
We multiply parentheses
4x-(2(x+11))-12=0
We calculate terms in parentheses: -(2(x+11)), so:We get rid of parentheses
2(x+11)
We multiply parentheses
2x+22
Back to the equation:
-(2x+22)
4x-2x-22-12=0
We add all the numbers together, and all the variables
2x-34=0
We move all terms containing x to the left, all other terms to the right
2x=34
x=34/2
x=17
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