0,5+x=4(2x+1/8)

Solution for 0,5+x=4(2x+1/8) equation:

0.5+x=4(2x+1/8)

We move all terms to the left:

0.5+x-(4(2x+1/8))=0

We add all the numbers together, and all the variables

x-(4(+2x+1/8))+0.5=0

We multiply all the terms by the denominator


x*8))-(4(+2x+1+(0.5)*8))=0

We add all the numbers together, and all the variables

2x+x*8))-(4(=0

Wy multiply elements

8x^2+2x=0

a = 8; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·8·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*8}=\frac{-4}{16}
=-1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*8}=\frac{0}{16}
=0
$