(-5+2r)(-5+2r)=-5

Solution for (-5+2r)(-5+2r)=-5 equation:

(-5+2r)(-5+2r)=-5

We move all terms to the left:

(-5+2r)(-5+2r)-(-5)=0

We add all the numbers together, and all the variables

(2r-5)(2r-5)-(-5)=0

We add all the numbers together, and all the variables

(2r-5)(2r-5)+5=0

We multiply parentheses ..

(+4r^2-10r-10r+25)+5=0

We get rid of parentheses

4r^2-10r-10r+25+5=0

We add all the numbers together, and all the variables

4r^2-20r+30=0

a = 4; b = -20; c = +30;
Δ = b2-4ac
Δ = -202-4·4·30
Δ = -80
Delta is less than zero, so there is no solution for the equation