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4(x+5)2-(2x+1)2=3(x-5)+180
We move all terms to the left:
4(x+5)2-(2x+1)2-(3(x-5)+180)=0
We multiply parentheses
8x-4x-(3(x-5)+180)+40-2=0
We calculate terms in parentheses: -(3(x-5)+180), so:We add all the numbers together, and all the variables
3(x-5)+180
We multiply parentheses
3x-15+180
We add all the numbers together, and all the variables
3x+165
Back to the equation:
-(3x+165)
4x-(3x+165)+38=0
We get rid of parentheses
4x-3x-165+38=0
We add all the numbers together, and all the variables
x-127=0
We move all terms containing x to the left, all other terms to the right
x=127
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