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0.25+x(1-x)=10(0.5-x)(0.5-x)
We move all terms to the left:
0.25+x(1-x)-(10(0.5-x)(0.5-x))=0
We add all the numbers together, and all the variables
x(-1x+1)-(10(-1x+0.5)(-1x+0.5))+0.25=0
We multiply parentheses
-1x^2+x-(10(-1x+0.5)(-1x+0.5))+0.25=0
We multiply parentheses ..
-1x^2-(10(+x^2-0.5x-0.5x+0.25))+x+0.25=0
We calculate terms in parentheses: -(10(+x^2-0.5x-0.5x+0.25)), so:We add all the numbers together, and all the variables
10(+x^2-0.5x-0.5x+0.25)
We multiply parentheses
10x^2+0x+0x+2.5
We add all the numbers together, and all the variables
10x^2+2x+2.5
Back to the equation:
-(10x^2+2x+2.5)
-1x^2+x-(10x^2+2x+2.5)+0.25=0
We get rid of parentheses
-1x^2-10x^2+x-2x-2.5+0.25=0
We add all the numbers together, and all the variables
-11x^2-1x-2.25=0
a = -11; b = -1; c = -2.25;
Δ = b2-4ac
Δ = -12-4·(-11)·(-2.25)
Δ = -98
Delta is less than zero, so there is no solution for the equation
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