4(x+5)2-(2x+1)=3(x-5)+180

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Solution for 4(x+5)2-(2x+1)=3(x-5)+180 equation: 



4(x+5)2-(2x+1)=3(x-5)+180

We move all terms to the left:

4(x+5)2-(2x+1)-(3(x-5)+180)=0

We multiply parentheses

8x-(2x+1)-(3(x-5)+180)+40=0

We get rid of parentheses

8x-2x-(3(x-5)+180)-1+40=0



We calculate terms in parentheses: -(3(x-5)+180), so:

3(x-5)+180

We multiply parentheses

3x-15+180

We add all the numbers together, and all the variables

3x+165

Back to the equation:

-(3x+165)



We add all the numbers together, and all the variables

6x-(3x+165)+39=0

We get rid of parentheses

6x-3x-165+39=0

We add all the numbers together, and all the variables

3x-126=0

We move all terms containing x to the left, all other terms to the right

3x=126

x=126/3

x=42

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