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4(3x+5)-6(3x-7)=11x+3(2x-9)
We move all terms to the left:
4(3x+5)-6(3x-7)-(11x+3(2x-9))=0
We multiply parentheses
12x-18x-(11x+3(2x-9))+20+42=0
We calculate terms in parentheses: -(11x+3(2x-9)), so:We add all the numbers together, and all the variables
11x+3(2x-9)
We multiply parentheses
11x+6x-27
We add all the numbers together, and all the variables
17x-27
Back to the equation:
-(17x-27)
-6x-(17x-27)+62=0
We get rid of parentheses
-6x-17x+27+62=0
We add all the numbers together, and all the variables
-23x+89=0
We move all terms containing x to the left, all other terms to the right
-23x=-89
x=-89/-23
x=3+20/23
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