(x+0.3)(x+0.3)=0.16

Solution for (x+0.3)(x+0.3)=0.16 equation:

(x+0.3)(x+0.3)=0.16

We move all terms to the left:

(x+0.3)(x+0.3)-(0.16)=0

We add all the numbers together, and all the variables

(x+0.3)(x+0.3)-0.16=0

We multiply parentheses ..

(+x^2+0.3x+0.3x+0.09)-0.16=0

We get rid of parentheses

x^2+0.3x+0.3x+0.09-0.16=0

We add all the numbers together, and all the variables

x^2+0.6x-0.07=0

a = 1; b = 0.6; c = -0.07;
Δ = b2-4ac
Δ = 0.62-4·1·(-0.07)
Δ = 0.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.6)-\sqrt{0.64}}{2*1}=\frac{-0.6-\sqrt{0.64}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.6)+\sqrt{0.64}}{2*1}=\frac{-0.6+\sqrt{0.64}}{2}
$