8x-2(x-4)=4(x-2)+10

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Solution for 8x-2(x-4)=4(x-2)+10 equation: 



8x-2(x-4)=4(x-2)+10

We move all terms to the left:

8x-2(x-4)-(4(x-2)+10)=0

We multiply parentheses

8x-2x-(4(x-2)+10)+8=0



We calculate terms in parentheses: -(4(x-2)+10), so:

4(x-2)+10

We multiply parentheses

4x-8+10

We add all the numbers together, and all the variables

4x+2

Back to the equation:

-(4x+2)



We add all the numbers together, and all the variables

6x-(4x+2)+8=0

We get rid of parentheses

6x-4x-2+8=0

We add all the numbers together, and all the variables

2x+6=0

We move all terms containing x to the left, all other terms to the right

2x=-6

x=-6/2

x=-3

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