4(3k-1)+3=7(k-3)+10

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Solution for 4(3k-1)+3=7(k-3)+10 equation: 



4(3k-1)+3=7(k-3)+10

We move all terms to the left:

4(3k-1)+3-(7(k-3)+10)=0

We multiply parentheses

12k-(7(k-3)+10)-4+3=0



We calculate terms in parentheses: -(7(k-3)+10), so:

7(k-3)+10

We multiply parentheses

7k-21+10

We add all the numbers together, and all the variables

7k-11

Back to the equation:

-(7k-11)



We add all the numbers together, and all the variables

12k-(7k-11)-1=0

We get rid of parentheses

12k-7k+11-1=0

We add all the numbers together, and all the variables

5k+10=0

We move all terms containing k to the left, all other terms to the right

5k=-10

k=-10/5

k=-2

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