(6x-40)+(8x+20)=(6x+60)+6x

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Solution for (6x-40)+(8x+20)=(6x+60)+6x equation:



(6x-40)+(8x+20)=(6x+60)+6x
We move all terms to the left:
(6x-40)+(8x+20)-((6x+60)+6x)=0
We get rid of parentheses
6x+8x-((6x+60)+6x)-40+20=0
We calculate terms in parentheses: -((6x+60)+6x), so:
(6x+60)+6x
We add all the numbers together, and all the variables
6x+(6x+60)
We get rid of parentheses
6x+6x+60
We add all the numbers together, and all the variables
12x+60
Back to the equation:
-(12x+60)
We add all the numbers together, and all the variables
14x-(12x+60)-20=0
We get rid of parentheses
14x-12x-60-20=0
We add all the numbers together, and all the variables
2x-80=0
We move all terms containing x to the left, all other terms to the right
2x=80
x=80/2
x=40

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