5p(p+4)=3p=

Solution for 5p(p+4)=3p= equation:

5p(p+4)=3p=

We move all terms to the left:

5p(p+4)-(3p)=0

We add all the numbers together, and all the variables

-3p+5p(p+4)=0

We multiply parentheses

5p^2-3p+20p=0

We add all the numbers together, and all the variables

5p^2+17p=0

a = 5; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·5·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*5}=\frac{-34}{10}
=-3+2/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*5}=\frac{0}{10}
=0
$