4(3-x)+(2x-5)=17

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Solution for 4(3-x)+(2x-5)=17 equation: 



4(3-x)+(2x-5)=17

We move all terms to the left:

4(3-x)+(2x-5)-(17)=0

We add all the numbers together, and all the variables

4(-1x+3)+(2x-5)-17=0

We multiply parentheses

-4x+(2x-5)+12-17=0

We get rid of parentheses

-4x+2x-5+12-17=0

We add all the numbers together, and all the variables

-2x-10=0

We move all terms containing x to the left, all other terms to the right

-2x=10

x=10/-2

x=-5

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