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3x+2x+(10x-8)+(5x-12)+120=540
We move all terms to the left:
3x+2x+(10x-8)+(5x-12)+120-(540)=0
We add all the numbers together, and all the variables
5x+(10x-8)+(5x-12)-420=0
We get rid of parentheses
5x+10x+5x-8-12-420=0
We add all the numbers together, and all the variables
20x-440=0
We move all terms containing x to the left, all other terms to the right
20x=440
x=440/20
x=22
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