a(a+5)+10=(a+2)(a+4)

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Solution for a(a+5)+10=(a+2)(a+4) equation: 



a(a+5)+10=(a+2)(a+4)

We move all terms to the left:

a(a+5)+10-((a+2)(a+4))=0

We multiply parentheses

a^2+5a-((a+2)(a+4))+10=0

We multiply parentheses ..

a^2-((+a^2+4a+2a+8))+5a+10=0



We calculate terms in parentheses: -((+a^2+4a+2a+8)), so:

(+a^2+4a+2a+8)

We get rid of parentheses

a^2+4a+2a+8

We add all the numbers together, and all the variables

a^2+6a+8

Back to the equation:

-(a^2+6a+8)



We add all the numbers together, and all the variables

a^2+5a-(a^2+6a+8)+10=0

We get rid of parentheses

a^2-a^2+5a-6a-8+10=0

We add all the numbers together, and all the variables

-1a+2=0

We move all terms containing a to the left, all other terms to the right

-a=-2

a=-2/-1

a=+2

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