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(4(5+x))/3=2x+2
We move all terms to the left:
(4(5+x))/3-(2x+2)=0
We add all the numbers together, and all the variables
(4(x+5))/3-(2x+2)=0
We get rid of parentheses
(4(x+5))/3-2x-2=0
We multiply all the terms by the denominator
(4(x+5))-2x*3-2*3=0
We calculate terms in parentheses: +(4(x+5)), so:We add all the numbers together, and all the variables
4(x+5)
We multiply parentheses
4x+20
Back to the equation:
+(4x+20)
(4x+20)-2x*3-6=0
Wy multiply elements
(4x+20)-6x-6=0
We get rid of parentheses
4x-6x+20-6=0
We add all the numbers together, and all the variables
-2x+14=0
We move all terms containing x to the left, all other terms to the right
-2x=-14
x=-14/-2
x=+7
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